Dynamic Column Name in LinQ
string columnName="exampleColumn";
items.Select(x => x.GetType().GetProperty(columnName).GetValue(x));
items.Select(x => x.GetType().GetProperty("Name").GetValue(x));
string columnName="exampleColumn";
items.Select(x => x.GetType().GetProperty(columnName).GetValue(x));
items.Select(x => x.GetType().GetProperty("Name").GetValue(x));
Yorumlar
Yorum Gönder